document.write( "Question 319076: THE DIGIT AT TEN,S PLACE OF A TWO DIGIT NUMBER IS TWICE THE DIGIT AT THE ONE,S PLACE . IF THE SUM OF THIS NUMBER AND NUMBER FORMED BY REVERSING THE DIGIT IS 66. FIND THE NUMBERS? \n" ); document.write( "
Algebra.Com's Answer #228418 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let AB be your digit or numerically 10*A+B. \n" ); document.write( "The reverse digit number is BA or numerically 10*B+A. \n" ); document.write( "1. \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "2. \n" ); document.write( "Substitute eq. 1 into eq. 2, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then from eq. 1, \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "The original number is 24, the reverse number is 42. \n" ); document.write( " |