document.write( "Question 319076: THE DIGIT AT TEN,S PLACE OF A TWO DIGIT NUMBER IS TWICE THE DIGIT AT THE ONE,S PLACE . IF THE SUM OF THIS NUMBER AND NUMBER FORMED BY REVERSING THE DIGIT IS 66. FIND THE NUMBERS? \n" ); document.write( "
Algebra.Com's Answer #228418 by Fombitz(32388)\"\" \"About 
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Let AB be your digit or numerically 10*A+B.
\n" ); document.write( "The reverse digit number is BA or numerically 10*B+A.
\n" ); document.write( "1.\"A=2B\"
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\n" ); document.write( "\"10A%2BB%2B10B%2BA=66\"
\n" ); document.write( "\"11A%2B11B=66\"
\n" ); document.write( "2.\"A%2BB=6\"
\n" ); document.write( "Substitute eq. 1 into eq. 2,
\n" ); document.write( "\"2B%2BB=6\"
\n" ); document.write( "\"3B=6\"
\n" ); document.write( "\"highlight%28B=2%29\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"highlight%28A=4%29\"
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\n" ); document.write( "The original number is 24, the reverse number is 42.
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