document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=319088>Question 319088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two circles each with radius of 1 are inscribed so that their centers lie along the diagonal of the square . Each circle is tangent to two sides of the square and they are tangent to each other. Find the area between the circles and the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228416 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228416\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diagonal of the square is 4.<BR>\n" );
document.write( "2a^2=c^2 Pythagoras<BR>\n" );
document.write( "2a^2=16<BR>\n" );
document.write( "a^2=8<BR>\n" );
document.write( "a=sqrt(4*2)<BR>\n" );
document.write( "=2sqrt(2) side of square<BR>\n" );
document.write( "a^2=8 area of square<BR>\n" );
document.write( ".<BR>\n" );
document.write( "A=pi*r^2<BR>\n" );
document.write( "=pi area of one of the circles<BR>\n" );
document.write( "2pi area of both circles<BR>\n" );
document.write( ".<BR>\n" );
document.write( "8-2pi= area between the circles and the square.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );