document.write( "Question 319073: ONE OF THE TWO NUMBERS EXCEEDS THE OTHER BY SEVEN AND IF WE ADD FOUR TIMES THE SMALLER TO FIVE TIMES THE GREATER WE GET 143.FIND THE NUMBERS? \n" ); document.write( "
Algebra.Com's Answer #228402 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "Let's have x be the smaller and (x+7) be the larger number. Here's the equation that can be setup:
\n" ); document.write( "4x+5(x+7)=143
\n" ); document.write( "Combine like terms to get:
\n" ); document.write( "9x+35=143
\n" ); document.write( "Subtract 35 from both sides to get:
\n" ); document.write( "9x=108
\n" ); document.write( "Divide by 9 to result in:
\n" ); document.write( "x=12
\n" ); document.write( "So the numbers are:
\n" ); document.write( "12 & 19
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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