document.write( "Question 319011: What three consecutive odd numbers have a product of 12075?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #228394 by CharlesG2(834)\"\" \"About 
You can put this solution on YOUR website!
What three consecutive odd numbers have a product of 12075?\r
\n" ); document.write( "\n" ); document.write( "factoring 12075\r
\n" ); document.write( "\n" ); document.write( "12075 = 25 * 483
\n" ); document.write( "(483 must be divisable by 3
\n" ); document.write( "because 4 + 8 + 3 = 15 and that is divisable by 3)
\n" ); document.write( "12075 = 25 * 3 * 161
\n" ); document.write( "(161 must be divisable by 7
\n" ); document.write( "because 7 * 10 = 70, 70 * 2 = 140, 3 * 7 = 21, and 140 + 21 = 161)
\n" ); document.write( "12075 = 25 * 3 * 7 * 23
\n" ); document.write( "(23 is a prime number, so it can not be factored)
\n" ); document.write( "12075 = 21 * 23 * 25 (these are your consecutive odd numbers)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );