document.write( "Question 318961: how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 20% anitfreeze to get a mixture that is 50% antifreeze? \n" ); document.write( "

Algebra.Com's Answer #228353 by Fombitz(32388) $\"\"$ $\"About$

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Let X be the number of gallons of 60% solution.
\n" ); document.write( "Write the concentration equation,
\n" ); document.write( " $\"60X%2B20%2890%29=50%28X%2B90%29\"$
\n" ); document.write( " $\"60X%2B1800=50X%2B4500\"$
\n" ); document.write( " $\"10X=2700\"$
\n" ); document.write( " $\"highlight%28X=270%29\"$ gallons \n" ); document.write( "

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