document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318998>Question 318998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Iam struggling with this problem it needs to be solved and rechecked. 1/5+y=-3/10. I have 1/5+y+-5/1<BR>\n" );
document.write( "            =3/10+-1/5<BR>\n" );
document.write( "            y=3/10+-1/5<BR>\n" );
document.write( "            this vis vwhere the denominators should come in on the next step. I'm lost at this point...plz help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228339 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/5 +y=-3/10<BR>\n" );
document.write( "y= -3/10 -1/5<BR>\n" );
document.write( "LCM for the right side = 10<BR>\n" );
document.write( "y= -3-2 / 10<BR>\n" );
document.write( "y=-5 / 10<BR>\n" );
document.write( "y=-1/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );