document.write( "Question 318955: Can anyone help me with this probability question? A box has the following six letters: R A N D O M . What is the probability of the outcome D A N in that order if three letters are drawn one by one 1)with replacement 2) without replacement? I could make a chart or tree if there were only two letters but I'm not sure how to solve with three. I know I've got one in six chances to pull individual letters, but I'm not sure how to work the other factors in. Any help would be appreciated! \n" ); document.write( "
Algebra.Com's Answer #228327 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A box has the following six letters: R A N D O M .
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\n" ); document.write( "What is the probability of the outcome D A N in that order if three letters are drawn one by one
\n" ); document.write( "1)with replacement
\n" ); document.write( "1st letter \"D\": 1/6
\n" ); document.write( "2nd letter \"A\"; 1/6
\n" ); document.write( "3rd letter \"N\": 1/6
\n" ); document.write( "------
\n" ); document.write( "Probability of outcome DAN with replacement = (1/6)^3 = 1/216
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\n" ); document.write( "\n" ); document.write( "2) without replacement?
\n" ); document.write( "1st letter \"D\": 1/6
\n" ); document.write( "2nd letter \"A\": 1/5
\n" ); document.write( "3rd letter \"N\": 1/4
\n" ); document.write( "-------------------------
\n" ); document.write( "Probability of outcome DAN without replacement = 1/(6*5*4) = 1/120
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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