document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318939>Question 318939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the difference of two numbers is 6. Their sum is 30. Find the two numbers.<BR>\n" );
document.write( "please show all work  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228321 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228321\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the difference of two numbers is 6. Their sum is 30. Find the two numbers.<BR>\n" );
document.write( "please show all work \r<BR>\n" );
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document.write( "Let x and y be the two numbers.  Then we have:\r<BR>\n" );
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document.write( "1.) x - y = 6 and<BR>\n" );
document.write( "2.) x + y = 30\r<BR>\n" );
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document.write( "From 1.) we have x = y + 6.  Substituting y + 6 for x in 2.) we have:\r<BR>\n" );
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document.write( "(y+6) + y = 30<BR>\n" );
document.write( "2y = 24<BR>\n" );
document.write( "y = 12\r<BR>\n" );
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document.write( "Since x = y + 6 we have x = 12 + 6 = 18  </SPAN>\n" );
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