document.write( "Question 318665: word problem from chapter on quadratic equations: Pipe A can fill a tank in 4 hrs. If pipe B works alone, it takes 3 hrs longer to fill the tank than if both pipes work together. How long will it take for pipe B to fill the tank if it works alone? \n" ); document.write( "
Algebra.Com's Answer #228288 by ankor@dixie-net.com(22740)\"\" \"About 
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Pipe A can fill a tank in 4 hrs. If pipe B works alone,
\n" ); document.write( " it takes 3 hrs longer to fill the tank than if both pipes work together.
\n" ); document.write( " How long will it take for pipe B to fill the tank if it works alone?
\n" ); document.write( ";
\n" ); document.write( "Let b = time required by pipe B working alone
\n" ); document.write( "then
\n" ); document.write( "(b-3) = time required when A & B are working together
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1 (a full tank)
\n" ); document.write( ":
\n" ); document.write( "A shared work equation
\n" ); document.write( "\"%28%28b-3%29%29%2F4\" + \"%28%28b-3%29%29%2Fb\" = 1
\n" ); document.write( "multiply by 4b, results:
\n" ); document.write( "b(b-3) + 4(b-3) = 4b
\n" ); document.write( ":
\n" ); document.write( "b^2 - 3b + 4b - 12 = 4b
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "b^2 - 3b + 4b - 4b - 12 = 0
\n" ); document.write( ":
\n" ); document.write( "b^2 - 3b - 12 = 0
\n" ); document.write( "Use the quadratic formula to find b
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "in this equation, x=b; a=1; b=-3; c=-12
\n" ); document.write( "\"b+=+%28-%28-3%29+%2B-+sqrt%28-3%5E2-4%2A1%2A-12%29%29%2F%282%2A1%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"b+=+%283+%2B-+sqrt%289+-%28-48%29%29%29%2F2+\"
\n" ); document.write( ":
\n" ); document.write( "\"b+=+%283+%2B-+sqrt%2857%29%29%2F2+\"
\n" ); document.write( "the positive solution is what we want here
\n" ); document.write( "\"b+=+%283+%2B+7.55%29%2F2+\"
\n" ); document.write( "b = \"10.55%2F2\"
\n" ); document.write( "b = 5.275 hrs is the time for B to fill the pool alone
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "see if that's true, (2.275 hrs for both working together)
\n" ); document.write( "\"2.275%2F4\" + \"2.275%2F5.275\" =
\n" ); document.write( ".56875 + .43128 = 1.000; confirms our solution
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