document.write( "Question 318798: Divide: (20b^3+7b^2+22b+23) divided by (4b+3) \n" ); document.write( "

Algebra.Com's Answer #228201 by CharlesG2(834) $\"\"$ $\"About$

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Divide: (20b^3+7b^2+22b+23) divided by (4b+3)\r
\n" ); document.write( "\n" ); document.write( "okay this is just like a regular long division problem, except you got the variable b thrown in there\r
\n" ); document.write( "\n" ); document.write( " 5b^2 - 2b + 7
\n" ); document.write( "4b + 3 --> 20b^3 + 7b^2 + 22b + 23
\n" ); document.write( " 20b^3 + 15b^2
\n" ); document.write( " - 8b^2 + 22b
\n" ); document.write( " - 8b^2 - 6b
\n" ); document.write( " 28b + 23
\n" ); document.write( " 28b + 21
\n" ); document.write( " 2 (there is a remainder)
\n" ); document.write( "5b^2 - 2b + 7 + 2/(4b + 3)\r
\n" ); document.write( "\n" ); document.write( "check (4b + 3)(5b^2 - 2b + 7):
\n" ); document.write( "20b^3 - 8b^2 + 28b
\n" ); document.write( " + 15b^2 - 6b + 21 =
\n" ); document.write( "20b^3 + 7b^2 + 22b + 21 \n" ); document.write( "

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