document.write( "Question 37125: Please help\r
\n" ); document.write( "\n" ); document.write( "solve each equation. Round your answers to the nearest hundreth, if necessary.\r
\n" ); document.write( "\n" ); document.write( "1. 4/3(x squared +12)-25=11
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Algebra.Com's Answer #22819 by weepingwillowcats(10)\"\" \"About 
You can put this solution on YOUR website!
\"%284%2F3%29%2A%28sqrt%28x%29%2B12%29-25=11\"add 25 to both sides
\n" ); document.write( "\"%284%2F3%29%2A%28sqrt%28x%29%2B12%29=36\"divide by 4/3
\n" ); document.write( "\"sqrt%28x%29%2B12=27\"subtract 12 from both sides
\n" ); document.write( "\"sqrt%28x%29=15\"square both sides
\n" ); document.write( "\"x=225\"
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