document.write( "Question 318736: Find three consecutive integers such that the square of the sum of the smaller two is 297 more than the square of the largest. \n" ); document.write( "
Algebra.Com's Answer #228158 by mananth(16946)\"\" \"About 
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let the integers be x, x+1, x+2
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\n" ); document.write( "(x+x+1)^2 = (x+2)^2 +297
\n" ); document.write( "(2x+1)^2=x^2+4x+4+297
\n" ); document.write( "4x^2+4x+1= x^2+4x+301
\n" ); document.write( "3x^2-300=0
\n" ); document.write( "3x^2=300
\n" ); document.write( "x^2=300/3
\n" ); document.write( "x^2=100
\n" ); document.write( "x=10
\n" ); document.write( "the integers are 10,11,12
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