document.write( "Question 318717: given that 1\n" ); document.write( "
Algebra.Com's Answer #228152 by jim_thompson5910(35256)\"\" \"About 
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You may be tempted to think that \"abs%28x%29=x\", but that is not true for all 'x'. It is only true if 'x' is positive. This is where you made a mistake. You're thinking that \"abs%28x-9%29=x-9\", but with the given domain, this is not true.\r
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\n" ); document.write( "\n" ); document.write( "Recall that \"abs%28x%29=x\" if 'x' is positive. So \"abs%28x%2B7%29=x%2B7\" if \"x%2B7%3E0\". Solve for 'x' to get \"x%3E-7\". Since \"1%3Cx%3C4\", this means that \"x%3E-7\" is most certainly true and that \"abs%28x%2B7%29=x%2B7\" is also true.\r
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\n" ); document.write( "\n" ); document.write( "On the flip side, \"abs%28x%29=-x\" if \"x%3C0\" (ie x is negative). Notice that \"abs%28x-9%29=-%28x-9%29\" only because \"x-9%3C0\" means that \"x%3C9\" (which is certainly true since \"1%3Cx%3C4\"). So once again \"abs%28x-9%29=-%28x-9%29\"\r
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\n" ); document.write( "\n" ); document.write( "To recap, \"abs%28x%2B7%29=x%2B7\" and \"abs%28x-9%29=-%28x-9%29\". If this makes no sense at all why these two equations hold, just graph the two functions with the domain \"1%3Cx%3C4\". Let's now use this info to simplify the expression.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28x%2B7%29-abs%28x-9%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B7%29-%28-%28x-9%29%29\" Plug in \"abs%28x%2B7%29=x%2B7\" and \"abs%28x-9%29=-%28x-9%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B7%2Bx-9\" Negate the negative\r
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\n" ); document.write( "\n" ); document.write( "\"2x-2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"abs%28x%2B7%29-abs%28x-9%29=2x-2\" where \"1%3Cx%3C4\"\r
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\n" ); document.write( "\n" ); document.write( "So for example, if \"x=2\", then \"abs%28x%2B7%29-abs%28x-9%29=abs%282%2B7%29-abs%282-9%29=abs%289%29-abs%28-7%29=9-7=2\" and also \"2x-2=2%282%29-2=4-2=2\" which confirms that \"abs%28x%2B7%29-abs%28x-9%29=2x-2\" when \"x=2\". We can use other numbers in the domain \"1%3Cx%3C4\" to reconfirm our answer.\r
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\n" ); document.write( "\n" ); document.write( "A better confirmation would be to graph \"y=abs%28x%2B7%29-abs%28x-9%29\" and \"y=2x-2\" to see that the two graphs match up completely over the domain \"1%3Cx%3C4\"
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