document.write( "Question 318691: Three numbers are positive consecutive odd integers. If the larger two numbers have a product of 195, find all three integers. \n" ); document.write( "

Algebra.Com's Answer #228148 by texttutoring(324) $\"\"$ $\"About$

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Let x = the first integer
\n" ); document.write( "Let x + 2 = the second integer (because 3 is 2 more than 1, and 5 is 2 more than 3, and so on...)\r
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\n" ); document.write( "\n" ); document.write( "Let x + 4 = the 3rd integer\r
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\n" ); document.write( "\n" ); document.write( "The two larger numbers (x+2) and x+4) multiply to 195.\r
\n" ); document.write( "\n" ); document.write( "195 = (x+2)(x+4)
\n" ); document.write( "195 = x^2 + 6x + 8\r
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\n" ); document.write( "\n" ); document.write( "You have to factor this to solve it:\r
\n" ); document.write( "\n" ); document.write( "0 = x^2 +6x +8 -195
\n" ); document.write( "0 = x^2+6x-187\r
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\n" ); document.write( "\n" ); document.write( "To factor this, you have to find 2 numbers that multiply to -195 and have a difference of 6. Or you could use the Quadratic Equation, with a=1 b=6 and c=-187\r
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\n" ); document.write( "\n" ); document.write( "Either way you will find that those numbers are -17 and 11. \r
\n" ); document.write( "\n" ); document.write( "The three numbers are either 11, 13, and 15 or -17, -15, and -13. \n" ); document.write( "

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