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the original equation:
\n" ); document.write( "(3/4-2/3)+(1/2+1/3)
\n" ); document.write( "according to order of operations (pemdas), we need to solve what is within the parenthesis first.
\n" ); document.write( "first, 3/4-2/3.
\n" ); document.write( "we have to convert these numbers into two fractions with the same denominator.
\n" ); document.write( "we will convert them both to a denominator of twelve.
\n" ); document.write( "3/4 --> 9/12 (we multiply the numerator and denominator by 3)
\n" ); document.write( "2/3 --> 8/12 (we multiply the numerator and denominator by 4)
\n" ); document.write( "so in the first parenthesis, we now have:
\n" ); document.write( "9/12 - 8/12, or 1/12.
\n" ); document.write( "now our equation is 1/12+(1/2+1/3)
\n" ); document.write( "in the second parenthesis, we need to again convert 1/2 and 1/3 into fractions with the same denominator. we will use 6 this time.
\n" ); document.write( "1/2 --> 3/6 (multiplied by 3)
\n" ); document.write( "1/3 --> 2/6 (multiplied by 2)
\n" ); document.write( "now in the parenthesis we have 3/6 + 2/6, or 5/6
\n" ); document.write( "so our equation is now:
\n" ); document.write( "1/12 + 5/6
\n" ); document.write( "again, we convert the fractions so they have the same denominator, in this case, 12.
\n" ); document.write( "1/12 stays the same.
\n" ); document.write( "5/6 --> 10/12 (multiplied by 2)
\n" ); document.write( "so we now have 1/12+10/12, which is 11/12.
\n" ); document.write( "(3/4-2/3)+(1/2+1/3) = 11/12. \n" ); document.write( "