document.write( "Question 318448: Replacement times for TV sets are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years. \r
\n" ); document.write( "\n" ); document.write( "A) find the probability that a randomly selected TV will have a replacement time less than 6.0 years.\r
\n" ); document.write( "\n" ); document.write( "B) If you want to provide a warranty so that only 1% of the TV sets will be replaced before the warranty expires, what is the time length of that warranty?
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Algebra.Com's Answer #228066 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
a) Find the z score.
\n" ); document.write( "\"z=%28x-mu%29%2Fsigma=%286-8.2%29%2F1.1\"
\n" ); document.write( "\"z=-2\"
\n" ); document.write( "\"P%28x+%3C=+-2%29=0.02275\"
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\n" ); document.write( "b) Find z so that P(z)=0.01.
\n" ); document.write( "\"z=-2.3264\"
\n" ); document.write( "\"%28x-8.2%29%2F1.1=-2.3264\"
\n" ); document.write( "\"x-8.2=-2.559\"
\n" ); document.write( "\"x=5.64\" yrs
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