document.write( "Question 318594: The perimeter of a rectangle is 92 if the widths were doubled and the lengths increased by 12 the new perimeter would be 140. What are the length and width of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #228052 by JBarnum(2146) $\"\"$ $\"About$

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p=92
\n" ); document.write( "p=2(L+W)
\n" ); document.write( " $\"92=2%28L%2BW%29\"$ = $\"46=%28L%2BW%29\"$
\n" ); document.write( " $\"140=2%28%28L%2B12%29%2B%282W%29%29\"$ = $\"70=%28%28L%2B12%29%2B%282W%29%29\"$ = $\"58=L%2B2W\"$
\n" ); document.write( "

\n" ); document.write( " $\"58=L%2B2W\"$ i will use the subtraction property of elimination method
\n" ); document.write( " $\"46=L%2BW\"$
\n" ); document.write( " $\"12=0%2BW\"$
\n" ); document.write( " $\"12=W\"$
\n" ); document.write( "

\n" ); document.write( " $\"46=L%2BW\"$
\n" ); document.write( " $\"46=L%2B12\"$
\n" ); document.write( " $\"34=L\"$
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\n" ); document.write( "Checking
\n" ); document.write( " $\"140=2%28%28%2834%29%2B12%29%2B%282%2812%29%29%29\"$
\n" ); document.write( " $\"140=2%28%2846%29%2B%2824%29%29\"$
\n" ); document.write( " $\"140=2%2870%29\"$
\n" ); document.write( " $\"140=140\"$
\n" ); document.write( "correct\r
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