document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318544>Question 318544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would you find the answer to this problem? The polynomial 0.041h-0.018a-2.69 can be used to estimate the lung capicity, in liters, of a female with height h in cemntimeters and age a in years. How would you find the lung capicity of a 40 year old female who is 140 centimeters tall? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #228017 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=228017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=LC=0.041h-0.018a-2.69+ ALIGN=MIDDLE  ALT=\"LC=0.041h-0.018a-2.69+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "When <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=140 ALIGN=MIDDLE  ALT=\"h=140\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=40 ALIGN=MIDDLE  ALT=\"a=40\"   DISABLED_style= \"max-width:90%; height:auto;\" >, then<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=LC=0.041%28140%29-0.018%2840%29-2.69 ALIGN=MIDDLE  ALT=\"LC=0.041%28140%29-0.018%2840%29-2.69\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Use a calculator to get the products, then subtract to get the final result.<BR>\n" );
document.write( " </SPAN>\n" );
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