document.write( "Question 318498: One year from today, Amy will be two-thirds as old as Ann. Five years from today; Amy will be four-fifths as old as Ann. How old is Amy today? \n" ); document.write( "
Algebra.Com's Answer #227966 by mananth(16946)\"\" \"About 
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Let Ann's age be x now.
\n" ); document.write( "Amy's age be y
\n" ); document.write( "..
\n" ); document.write( "after one year
\n" ); document.write( "ann - x+1
\n" ); document.write( "Amy y+1
\n" ); document.write( "(y+1)= 2/3 (x+1)
\n" ); document.write( "3(y+1)=2(x+1)
\n" ); document.write( "3y+3=2x+2
\n" ); document.write( "1. 3y-2x=-1
\n" ); document.write( "..
\n" ); document.write( "After 5 years
\n" ); document.write( "Ann x+y
\n" ); document.write( "Amy y+5
\n" ); document.write( "..
\n" ); document.write( "y+5 = 4/5 (x+5)
\n" ); document.write( "5(y+5)=4(x+5)
\n" ); document.write( "5y+25=4x+20
\n" ); document.write( "2. 5y-4x=-5
\n" ); document.write( "Multiply eq1 by 2 and subtract eq2
\n" ); document.write( "6y-4x-5y+4x=-2+5
\n" ); document.write( "y=3 Ann's age now
\n" ); document.write( "plug the value of y in eq1
\n" ); document.write( "3y-2x=-1
\n" ); document.write( "9-2x=-1
\n" ); document.write( "10=2x
\n" ); document.write( "x=5 Amy's age now
\n" ); document.write( "
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