document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318512>Question 318512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rectangular room has width half of  its length. When 6 is decreased from both length and width then its area is differed by 108 so find the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227962 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x<BR>\n" );
document.write( "length will be 2x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "6 is decreased from both<BR>\n" );
document.write( "x-6 <BR>\n" );
document.write( "2x-6<BR>\n" );
document.write( "2x^2-(x-6)(2x-6)= 108<BR>\n" );
document.write( "2x^2-(2x^2-6x-12x+36)=108<BR>\n" );
document.write( "2x^2-2x^2+18x-36=108<BR>\n" );
document.write( "18x=108+36<BR>\n" );
document.write( "18x=144<BR>\n" );
document.write( "x=144/18<BR>\n" );
document.write( "x=8 which is the width<BR>\n" );
document.write( "Length = 2x = 16 units </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );