document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318499>Question 318499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 100 square cm. If a square is built using a diagonal of this rectangle as one of its sides, the square has area 700 square cm. What is the perimeter of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227958 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227958\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length of rectangle= x<BR>\n" );
document.write( "widthof rectangle  =y<BR>\n" );
document.write( "area = xy =100<BR>\n" );
document.write( "..<BR>\n" );
document.write( "diagonal = sqrt(x^2+y^2)<BR>\n" );
document.write( "side of square = Sqrt(x^2+y^2)<BR>\n" );
document.write( "Area =sqrt(x^2+y^2)*sqrt(x^2+y^2)<BR>\n" );
document.write( "x^2+y^2=700<BR>\n" );
document.write( "add 2xy to both sides<BR>\n" );
document.write( "x^2+2xy+y^2=700+2xy<BR>\n" );
document.write( "(x+y)^2=700+2xy<BR>\n" );
document.write( "(x+y)^2=700+200<BR>\n" );
document.write( "(x+y)^2=900<BR>\n" );
document.write( "x+y=30<BR>\n" );
document.write( "Perimeter = 2(x+y)<BR>\n" );
document.write( "perimeter = 2*30=60 sq.cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );