document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318299>Question 318299</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I get the coordinates of the vertex of the graph of Y=x^2+2x-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227816 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for y-k = a(x-h)^2 , the vertex is (h,k)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "y+3 = x^2 + 2x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "completing the square ___ y+3+1 = x^2 + 2x + 1 ___ y+4 = (x+1)^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "vertex is ___ (-1,-4) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );