document.write( "Question 318204: find the locus of all points in a plane the are equidistant from points (-3,0) and (0,3) \n" ); document.write( "
Algebra.Com's Answer #227773 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use the distance formula,
\n" ); document.write( "\"D%5E2=%28x1-x2%29%5E2%2B%28y1-y2%29%5E2\"
\n" ); document.write( "Distance from (-3,0),
\n" ); document.write( "\"D1%5E2=%28x-%28-3%29%29%5E2%2B%28y-0%29%5E2\"
\n" ); document.write( "\"D1%5E2=%28x%2B3%29%5E2%2By%5E2\"
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\n" ); document.write( "Distance from (0,3),
\n" ); document.write( "\"D2%5E2=%28x-0%29%5E2%2B%28y-3%29%5E2=0\"
\n" ); document.write( "\"D2%5E2=x%5E2%2B%28y-3%29%5E2=0\"
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\n" ); document.write( "\"D1=D2\"
\n" ); document.write( "\"%28x%2B3%29%5E2%2By%5E2=x%5E2%2B%28y-3%29%5E2\"
\n" ); document.write( "\"x%5E2%2B3x%2B9%2By%5E2=x%5E2%2By%5E2-3y%2B9\"
\n" ); document.write( "\"cross%28x%5E2%29%2B3x%2B9%2Bcross%28y%5E2%29=cross%28x%5E2%29%2Bcross%28y%5E2%29-3y%2B9\"
\n" ); document.write( "\"3x%2B9=-3y%2B9\"
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\n" ); document.write( "All of the points on the line \"y=-x\" are equidistant from the two points.
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