document.write( "Question 318082: Suppose that g(x)is a linear function and also that g(1)=12 and g(-2)=-3. Find an algebraic formula for g(x).\r
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\n" ); document.write( "\n" ); document.write( "I am so lost here. I am probably reading way to far into this question but I have no idea where to start. Any help would be greatly appreciated.
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Algebra.Com's Answer #227726 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since g(1)=12 and g(-2)=-3, this means that the points (1,12) and (-2,-3) lie on the line. So all we need to do is find the equation of the line that goes through (1,12) and (-2,-3).\r
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\n" ); document.write( "\n" ); document.write( "First let's find the slope of the line through the points and \r
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\n" ); document.write( "\n" ); document.write( "Note: is the first point . So this means that \"x%5B1%5D=1\" and \"y%5B1%5D=12\".\r
\n" ); document.write( "\n" ); document.write( "Also, is the second point . So this means that \"x%5B2%5D=-2\" and \"y%5B2%5D=-3\".\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula.\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-3-12%29%2F%28-2-1%29\" Plug in \"y%5B2%5D=-3\", \"y%5B1%5D=12\", \"x%5B2%5D=-2\", and \"x%5B1%5D=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-15%29%2F%28-2-1%29\" Subtract \"12\" from \"-3\" to get \"-15\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28-15%29%2F%28-3%29\" Subtract \"1\" from \"-2\" to get \"-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope of the line that goes through the points and is \"m=5\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point slope formula:\r
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\n" ); document.write( "\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" Start with the point slope formula\r
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\n" ); document.write( "\n" ); document.write( "\"y-12=5%28x-1%29\" Plug in \"m=5\", \"x%5B1%5D=1\", and \"y%5B1%5D=12\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-12=5x%2B5%28-1%29\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y-12=5x-5\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=5x-5%2B12\" Add 12 to both sides. \r
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\n" ); document.write( "\n" ); document.write( "\"y=5x%2B7\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "So the equation that goes through the points and is \"y=5x%2B7\"\r
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\n" ); document.write( "\n" ); document.write( "Now simply replace 'y' with g(x) to get \"g%28x%29=5x%2B7\"\r
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\n" ); document.write( "\n" ); document.write( "So the linear function is \"g%28x%29=5x%2B7\"
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