document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317981>Question 317981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> have a machine, where only 2% of widgets produced are defective. I randomly select two widgets...? I have a machine, where only 2% of widgets produced are defective. I randomly select two widgets that have been produced by the machine. For the following questions, round to the nearest hundredth.\r<BR>\n" );
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document.write( "How many experimental outcomes yield 2 defects?\r<BR>\n" );
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document.write( "What is the P(no defects)?\r<BR>\n" );
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document.write( "What is the P(one defect)?\r<BR>\n" );
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document.write( "What is the P(two defects)? (Do not round for this problem)\r<BR>\n" );
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document.write( "Say we chose three widgets instead of two widgets, how many experimental outcomes would produce exactly one defect?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227715 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2% of widgets produced are defective. I randomly select two widgets that have been produced by the machine. For the following questions, round to the nearest hundredth.<BR>\n" );
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document.write( "How many experimental outcomes yield 2 defects?:::(0.02)^2 = 0.0004<BR>\n" );
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document.write( "What is the P(no defects)?::: (0.98)^2 = 0.9604<BR>\n" );
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document.write( "What is the P(one defect)?::: 1-[0.0004+0.9604] = 0.0392<BR>\n" );
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document.write( "What is the P(two defects)?::: (0.02)^2 = 0.0004  (Do not round for this problem) <BR>\n" );
document.write( "Say we chose three widgets instead of two widgets, how many experimental outcomes would produce exactly one defect?:::<BR>\n" );
document.write( "P(one defect) = 3C1(0.02)(0.98)^2 = 3*0.02*0.9604 = 0.0576<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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