document.write( "Question 317995: The perimeter of a rectangle is 140m. The length is 7m more than twice the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #227700 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+7 \n" ); document.write( "P=2L+2W \n" ); document.write( "140=2(2W+7)+2W \n" ); document.write( "140=4W+14+2W \n" ); document.write( "140=6W+14 \n" ); document.write( "6W=140-14 \n" ); document.write( "6W=126 \n" ); document.write( "W=126/6 \n" ); document.write( "W=21 m. ANS. \n" ); document.write( "L=2*21+7=42+7=49 m. ans. for the lengtrh. \n" ); document.write( "Proof:140=2*49=2*21 \n" ); document.write( "140=98+42 \n" ); document.write( "140=140 \n" ); document.write( " \n" ); document.write( " |