document.write( "Question 317995: The perimeter of a rectangle is 140m. The length is 7m more than twice the width. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #227700 by checkley77(12844)\"\" \"About 
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L=2W+7
\n" ); document.write( "P=2L+2W
\n" ); document.write( "140=2(2W+7)+2W
\n" ); document.write( "140=4W+14+2W
\n" ); document.write( "140=6W+14
\n" ); document.write( "6W=140-14
\n" ); document.write( "6W=126
\n" ); document.write( "W=126/6
\n" ); document.write( "W=21 m. ANS.
\n" ); document.write( "L=2*21+7=42+7=49 m. ans. for the lengtrh.
\n" ); document.write( "Proof:140=2*49=2*21
\n" ); document.write( "140=98+42
\n" ); document.write( "140=140
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