document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=37061>Question 37061</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072549017/algebrahomeworkh> </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution -\r<BR>\n" );
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document.write( "5x - 2y = -5<BR>\n" );
document.write( " y - 5x = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22770 by </B><A HREF=/tutors/aboutme.mpl?userid=jcmtnez><B>jcmtnez(53)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jcmtnez><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22770\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve by substitution \r<BR>\n" );
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document.write( "5x - 2y = -5   <BR>\n" );
document.write( " y - 5x = 3\r<BR>\n" );
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document.write( "(1) We isolate one variable, in this case the easiest is the y in the second equation, then we write:\r<BR>\n" );
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document.write( "y-5x=3,  and therefore y=3+5x\r<BR>\n" );
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document.write( "(2) Now we only have to substitute this the variable that we choose in this case y in the first equation.\r<BR>\n" );
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document.write( "5x-2y=-5<BR>\n" );
document.write( "Therefore,  5x-2(3+5x)=-5,  5x-6+10x=-5,  finally 15x=1, and the solution for x=1/15\r<BR>\n" );
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document.write( "(3) To obtain y we substitute the value of x in the equation that we have obtain before (y=3+5x)\r<BR>\n" );
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document.write( "y=3+5(1/15), y=3+1/3, y=10/3  \r<BR>\n" );
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document.write( " </SPAN>\n" );
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