document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=318017>Question 318017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor the following trinomial, if possible. If the coefficient of the first term is negative, factor out -1 to make the first term positive. Assume that n is a natural number. \r<BR>\n" );
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document.write( "y^4n - 2y^2n + 1 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227686 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227686\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^4n - 2y^2n + 1<BR>\n" );
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document.write( "=(y^2n -1)(y^2n -1)<BR>\n" );
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document.write( "= (y^n-1)(y^n+1)(y^n-1)(y^n+1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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