document.write( "Question 317946: write an equation of a line that passes through (2,3) and perpendicular to y=-5x+12. \n" ); document.write( "
Algebra.Com's Answer #227673 by checkley77(12844)\"\" \"About 
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Thru (2,3) and perpendicular to
\n" ); document.write( "y=-5x+12 (red line) this line has a slope (m)=-5.
\n" ); document.write( "The perpendicular line will have a slope=1/5.
\n" ); document.write( "Y =mX+b
\n" ); document.write( "3=1/5*2+b
\n" ); document.write( "3=2/5+b
\n" ); document.write( "b=3-2/5
\n" ); document.write( "b=15/5-2/5
\n" ); document.write( "b-13/5 ans. for the Y 9intercept.
\n" ); document.write( "Y=x/5-13/5 (green line
\n" ); document.write( " \"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-5x+%2B12%2C+x%2F5+-13%2F5%29+\" (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, of TWO functions -5x 12 and x/5 -13/5).
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