document.write( "Question 317956: The width or a rectangle is 2 feet less than the length. The area is 3 feet squared. Find the length and the width. \n" ); document.write( "
Algebra.Com's Answer #227667 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! W=L-2 \n" ); document.write( "A=LW \n" ); document.write( "3=L(L-2) \n" ); document.write( "3=L^2-2L \n" ); document.write( "L^2-2L-3=0 \n" ); document.write( "(L]-3)(L=1)=0 \n" ); document.write( "L-3=0 \n" ); document.write( "L=3 ANS. FOR THE LENGTH. \n" ); document.write( "W=3-2=1 ANS. FOR THE WIDTH. \n" ); document.write( "PROOF: \n" ); document.write( "3=3*1 \n" ); document.write( "3=3 \n" ); document.write( " |