document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317959>Question 317959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 30% copper should be mixed with 600oz of an alloy that is 60% copper in order to get alloy that is 40% copper?\r<BR>\n" );
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document.write( "I want to know if I set it up right.<BR>\n" );
document.write( ".30x + .60(600) = .40(360+x)<BR>\n" );
document.write( "Is that correct? ...because I'm not getting the answer I was told I should get. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227657 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227657\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  How much of an alloy that is 30% copper should be mixed with 600oz of an alloy that is 60% copper in order to get alloy that is 40% copper? <BR>\n" );
document.write( "I want to know if I set it up right.<BR>\n" );
document.write( ".30x + .60(600) = .40(360+x)<BR>\n" );
document.write( "Is that correct? ...because I'm not getting the answer I was told I should get.<BR>\n" );
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document.write( ".30x + .60(600) = .40(360+x) ** Why 360 + x ?  Should be 0.40*(600+x)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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