document.write( "Question 317970: I really need help with these last three problems and then I am done with the course! PLEASE HELP I am really confused....
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document.write( "(Solve by completing the square.)
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document.write( "1.x^2-6x=1\r
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document.write( "2.2x^2-3x+1=x0\r
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document.write( "3.x^2-x-1=0\r
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document.write( "Thank you for your time and help. \n" );
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Algebra.Com's Answer #227648 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (Solve by completing the square.) \n" ); document.write( "1.x^2-6x=1 \n" ); document.write( "x^2-6x+9 = 1+9 \n" ); document.write( "(x-3)^2 = 10 \n" ); document.write( "x-3 = sqrt(10) or x-3 = -sqrt(10) \n" ); document.write( "x = 3+sqrt(10) or x = 3-sqrt(10)\r \n" ); document.write( "\n" ); document.write( "-------------------------------------------------- \n" ); document.write( "2. 2x^2-3x+1= 0 \n" ); document.write( "2x^2 - 3x = -1 \n" ); document.write( "2(x^2-(3/2)x) = -1 \n" ); document.write( "2(x^2-(3/2)x+(3/4)^2) = -1 + 2(3/4)^2 \n" ); document.write( "2(x-(3/2))^2 = 1/8 \n" ); document.write( "(x-(3/2))^2 = 1/16 \n" ); document.write( "x-(3/2) = +-1/4 \n" ); document.write( "x = (3/2)+(1/4) or x = (3/2)-(1/4) \n" ); document.write( "x = (7/4) or x = 5/4 \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "3.x^2-x-1=0 \n" ); document.write( "I'll leave this one to you. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |