document.write( "Question 317970: I really need help with these last three problems and then I am done with the course! PLEASE HELP I am really confused....
\n" ); document.write( "(Solve by completing the square.)
\n" ); document.write( "1.x^2-6x=1\r
\n" ); document.write( "\n" ); document.write( "2.2x^2-3x+1=x0\r
\n" ); document.write( "\n" ); document.write( "3.x^2-x-1=0\r
\n" ); document.write( "\n" ); document.write( "Thank you for your time and help.
\n" ); document.write( "

Algebra.Com's Answer #227648 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(Solve by completing the square.)
\n" ); document.write( "1.x^2-6x=1
\n" ); document.write( "x^2-6x+9 = 1+9
\n" ); document.write( "(x-3)^2 = 10
\n" ); document.write( "x-3 = sqrt(10) or x-3 = -sqrt(10)
\n" ); document.write( "x = 3+sqrt(10) or x = 3-sqrt(10)\r
\n" ); document.write( "\n" ); document.write( "--------------------------------------------------
\n" ); document.write( "2. 2x^2-3x+1= 0
\n" ); document.write( "2x^2 - 3x = -1
\n" ); document.write( "2(x^2-(3/2)x) = -1
\n" ); document.write( "2(x^2-(3/2)x+(3/4)^2) = -1 + 2(3/4)^2
\n" ); document.write( "2(x-(3/2))^2 = 1/8
\n" ); document.write( "(x-(3/2))^2 = 1/16
\n" ); document.write( "x-(3/2) = +-1/4
\n" ); document.write( "x = (3/2)+(1/4) or x = (3/2)-(1/4)
\n" ); document.write( "x = (7/4) or x = 5/4
\n" ); document.write( "---------------------------------------------------
\n" ); document.write( "3.x^2-x-1=0
\n" ); document.write( "I'll leave this one to you.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" ); document.write( "
\n" );