document.write( "Question 317916: the height(inches) of the students on a campus is assumed to have a normal distribution with a sample standard deviation of 4 inches. A random sample of 49 students was taken with a sample mean of 60 inches. The 95% confidence interval for the population mean µ is :\r
\n" );
document.write( "\n" );
document.write( "A. 55.33-64.33
\n" );
document.write( "B. 58.88-61.12
\n" );
document.write( "C. 60.58-63.45
\n" );
document.write( "D. None of the above \n" );
document.write( "
Algebra.Com's Answer #227646 by stanbon(75887) ![]() You can put this solution on YOUR website! the height(inches) of the students on a campus is assumed to have a normal distribution with a sample standard deviation of 4 inches. \n" ); document.write( "------------------ \n" ); document.write( "A random sample of 49 students was taken with a sample mean of 60 inches. The 95% confidence interval for the population mean µ is ? \n" ); document.write( "--------------- \n" ); document.write( "sample mean: 60 \n" ); document.write( "ME = (invT(0.975 with df=48)*4/sqrt(49) \n" ); document.write( "ME = 2.0106*(4/7) = 1.148 \n" ); document.write( "--- \n" ); document.write( "95% CI: 60-01.148 < u < 61.148 \n" ); document.write( "95% CI: 58.85 < u < 61.15 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==============\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "A. 55.33-64.33 \n" ); document.write( "B. 58.88-61.12 \n" ); document.write( "C. 60.58-63.45 \n" ); document.write( "D. None of the above \n" ); document.write( " \n" ); document.write( " |