document.write( "Question 317905: factor completely 5X2 + 20X - 60 (note the 2 is squared) What I have for work is
\n" ); document.write( "=5(x2 + 5(4x) + 5(-12)
\n" ); document.write( "=5(x2 + 4x -12)\r
\n" ); document.write( "\n" ); document.write( "I think this is correct but not sure if there is more to be factored. Email address is 9-iron@wctc.net
\n" ); document.write( "

Algebra.Com's Answer #227632 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
factor completely 5X2 + 20X - 60 (note the 2 is squared) What I have for work is
\n" ); document.write( "=5(x2 + 5(4x) + 5(-12)
\n" ); document.write( "=5(x2 + 4x -12)
\n" ); document.write( "----
\n" ); document.write( "OK so far.
\n" ); document.write( "-----
\n" ); document.write( "To factor further,
\n" ); document.write( "think of two numbers whose product is -12 and whose sum is 4.
\n" ); document.write( "---
\n" ); document.write( "The numbers are +6 and -2
\n" ); document.write( "---
\n" ); document.write( "Rewrite the problem as:
\n" ); document.write( "= 5(x^2 +6x-2x -12)
\n" ); document.write( "Factor to get:
\n" ); document.write( "= 5[(x(x+6)-2(x+6)]
\n" ); document.write( "Factor again:
\n" ); document.write( "= 5(x+6)(x-2)
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===================
\n" ); document.write( "
\n" );