document.write( "Question 317905: factor completely 5X2 + 20X - 60 (note the 2 is squared) What I have for work is
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document.write( "=5(x2 + 5(4x) + 5(-12)
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document.write( "=5(x2 + 4x -12)\r
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document.write( "I think this is correct but not sure if there is more to be factored. Email address is 9-iron@wctc.net \n" );
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Algebra.Com's Answer #227632 by stanbon(75887) ![]() You can put this solution on YOUR website! factor completely 5X2 + 20X - 60 (note the 2 is squared) What I have for work is \n" ); document.write( "=5(x2 + 5(4x) + 5(-12) \n" ); document.write( "=5(x2 + 4x -12) \n" ); document.write( "---- \n" ); document.write( "OK so far. \n" ); document.write( "----- \n" ); document.write( "To factor further, \n" ); document.write( "think of two numbers whose product is -12 and whose sum is 4. \n" ); document.write( "--- \n" ); document.write( "The numbers are +6 and -2 \n" ); document.write( "--- \n" ); document.write( "Rewrite the problem as: \n" ); document.write( "= 5(x^2 +6x-2x -12) \n" ); document.write( "Factor to get: \n" ); document.write( "= 5[(x(x+6)-2(x+6)] \n" ); document.write( "Factor again: \n" ); document.write( "= 5(x+6)(x-2) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |