document.write( "Question 317902: Pamela requires 3 hours to swim 15 miles downstream in the illinois river. The return trip upstream takes 5 hours. Find Pamela's average speed in still water. How fast is the current?( assume that Pamela's speed is the same in each direction) \n" ); document.write( "
Algebra.Com's Answer #227631 by stanbon(75887) ![]() You can put this solution on YOUR website! Pamela requires 3 hours to swim 15 miles downstream in the illinois river. \n" ); document.write( "----- \n" ); document.write( "time = 3 hrs; distance = 15 miles ; rate = d/t = 15/3 = 5 mph \n" ); document.write( "-----------------------------\r \n" ); document.write( "\n" ); document.write( "The return trip upstream takes 5 hours. \n" ); document.write( "time = 5 hrs; distance = 15 miles ; rate = 15/5 = 3 mph \n" ); document.write( "------------------------------ \n" ); document.write( "Find Pamela's average speed in still water. \n" ); document.write( "How fast is the current?( assume that Pamela's speed is the same in each direction) \n" ); document.write( "--- \n" ); document.write( "Let her swim speed be \"s\": \n" ); document.write( "Let the current speed be \"c\"; \n" ); document.write( "Equations: \n" ); document.write( "Down stream: s + c = 5 mph \n" ); document.write( "up-stream::: s - c = 3 mph \n" ); document.write( "----------------- \n" ); document.write( "Add the two equations and solve for \"s\" \n" ); document.write( "2s = 8 mph \n" ); document.write( "s = 4 mph (Pamel's speed in still water. \n" ); document.write( "--- \n" ); document.write( "Since s+c=5, c = 1 mph (speed of the current) \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "===================== \n" ); document.write( " \n" ); document.write( " |