document.write( "Question 317854: Solve the system: \r
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document.write( "3c-d=1
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document.write( "3d+c=1 \n" );
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Algebra.Com's Answer #227618 by mananth(16949) You can put this solution on YOUR website! 1..3c-d=1 \n" ); document.write( "2..3d+c=1 \n" ); document.write( ".. \n" ); document.write( "multiply eq1 by 3 \n" ); document.write( "9c-3d=3 \n" ); document.write( "add to eq2 \n" ); document.write( "9c-3d+3d+c=4 \n" ); document.write( "10c=4 \n" ); document.write( "c=4/10 = 2/5 \n" ); document.write( ".. \n" ); document.write( "plug the value of c in eq1 \n" ); document.write( "3c-d=1 \n" ); document.write( "3*2/5-d=1 \n" ); document.write( "d=6/5 -1 \n" ); document.write( "d=6-5 / 5 \n" ); document.write( "d=1/5 \n" ); document.write( " |