document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317630>Question 317630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 100 animals consisting of cows, pigs and chickens.  He takes the animals to market and sells all of them for $100. <BR>\n" );
document.write( "He sells cows for $10<BR>\n" );
document.write( "He sells pigs for $3<BR>\n" );
document.write( "He sells chickens 2 for $1<BR>\n" );
document.write( "How many of each animal does he sell? (no 1/2 animals)\r<BR>\n" );
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document.write( "I came up with x+y+z=100 animals...<BR>\n" );
document.write( "and            10x+3y+0.5z=100 dollars<BR>\n" );
document.write( "I believe this needs another equation but I cannot figure it out.  Also we are working with arbitrary numbers in class.  Thank You! Scott M. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227584 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cows cost $10, Pigs cost $3, and chickens cost $.50. <BR>\n" );
document.write( "He only bought 100 animals and bought at least one of each animal. <BR>\n" );
document.write( "He only spent $100. How many of each animal did he buy?<BR>\n" );
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document.write( "Let c = no. of cows; p = no. of pigs; s = no. chickens<BR>\n" );
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document.write( "No. of animals equation:<BR>\n" );
document.write( " c + p + s  = 100<BR>\n" );
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document.write( "Cows cost $10, Pigs cost $3, and chickens cost $.50.<BR>\n" );
document.write( "the $$ equation:<BR>\n" );
document.write( "10c + 3p + .5s = 100<BR>\n" );
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document.write( "We have two equations but 3 unknowns, however, we know there can't very many cows,<BR>\n" );
document.write( "After trying a couple values for no. of cows, came up with 5 cows, <BR>\n" );
document.write( "they're worth $50, our two equations then are:<BR>\n" );
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document.write( "p + s = 100 - 5<BR>\n" );
document.write( "p + s =  95<BR>\n" );
document.write( "and<BR>\n" );
document.write( "3p + .5s = 100 - 50<BR>\n" );
document.write( "3p + .5s = 50<BR>\n" );
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document.write( "Multiply the 1st equation by 3 and subtract the 2nd equation:<BR>\n" );
document.write( "3p + 3s = 285<BR>\n" );
document.write( "3p + .5s = 50<BR>\n" );
document.write( "---------------- subtracting eliminates p<BR>\n" );
document.write( "0p + 2.5s = 235<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=235%2F2.5 ALIGN=MIDDLE  ALT=\"235%2F2.5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "s = 94 chickens<BR>\n" );
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document.write( "Find pigs<BR>\n" );
document.write( "p + 94 = 95<BR>\n" );
document.write( "p = 95 - 94<BR>\n" );
document.write( "p = 1 pig<BR>\n" );
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document.write( "We have then: 5 cows, 1 pig, 94 chicken<BR>\n" );
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document.write( ";<BR>\n" );
document.write( "Check in the cost equation<BR>\n" );
document.write( "10(5) + 3(1) + 94(.5) =<BR>\n" );
document.write( "50 + 3 + 47 = $100\r<BR>\n" );
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