document.write( "Question 317784: factorize 6x^2+17x+5 by splitting middle term snd by using the factor theorm \n" ); document.write( "
Algebra.Com's Answer #227548 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"6x%5E2%2B17x%2B5\", we can see that the first coefficient is \"6\", the second coefficient is \"17\", and the last term is \"5\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"6\" by the last term \"5\" to get \"%286%29%285%29=30\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"30\" (the previous product) and add to the second coefficient \"17\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"30\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"30\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,5,6,10,15,30\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-5,-6,-10,-15,-30\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"30\".\r
\n" ); document.write( "\n" ); document.write( "1*30 = 30
\n" ); document.write( "2*15 = 30
\n" ); document.write( "3*10 = 30
\n" ); document.write( "5*6 = 30
\n" ); document.write( "(-1)*(-30) = 30
\n" ); document.write( "(-2)*(-15) = 30
\n" ); document.write( "(-3)*(-10) = 30
\n" ); document.write( "(-5)*(-6) = 30\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"17\":\r
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First NumberSecond NumberSum
1301+30=31
2152+15=17
3103+10=13
565+6=11
-1-30-1+(-30)=-31
-2-15-2+(-15)=-17
-3-10-3+(-10)=-13
-5-6-5+(-6)=-11
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"2\" and \"15\" add to \"17\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"2\" and \"15\" both multiply to \"30\" and add to \"17\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"17x\" with \"2x%2B15x\". Remember, \"2\" and \"15\" add to \"17\". So this shows us that \"2x%2B15x=17x\".\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2Bhighlight%282x%2B15x%29%2B5\" Replace the second term \"17x\" with \"2x%2B15x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%286x%5E2%2B2x%29%2B%2815x%2B5%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%283x%2B1%29%2B%2815x%2B5%29\" Factor out the GCF \"2x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%283x%2B1%29%2B5%283x%2B1%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%2B5%29%283x%2B1%29\" Combine like terms. Or factor out the common term \"3x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"6x%5E2%2B17x%2B5\" factors to \"%282x%2B5%29%283x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"6x%5E2%2B17x%2B5=%282x%2B5%29%283x%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%282x%2B5%29%283x%2B1%29\" to get \"6x%5E2%2B17x%2B5\" or by graphing the original expression and the answer (the two graphs should be identical).
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