document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317718>Question 317718</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sue is now 7 times as old as louis. in 6 yearss, sue will be  5 times as old a louis. can you help me find the present age for both sue and louis </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227529 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this:<BR>\n" );
document.write( "Let S = Sue's present age and L = Louis's present age.<BR>\n" );
document.write( "1) S = 7L \"Sue is 7 times as old as Louis.\"<BR>\n" );
document.write( "2) S+6 = 5(L+6) \"In 6 years, Sue will be 5 times as old as Louis (will be in 6 years time)\" Substitute equation 1) into equation 2) and solve for L.<BR>\n" );
document.write( "2a) (7L)+6 = 5(L+6) Simplify.<BR>\n" );
document.write( "7L+6 = 5L+30 Subtract 5L from both sides.<BR>\n" );
document.write( "2L+6 = 30 Subtract 6 from both sides.<BR>\n" );
document.write( "2L = 24 Divide both sides by 2.<BR>\n" );
document.write( "L = 12 and...<BR>\n" );
document.write( "S = 7L<BR>\n" );
document.write( "S = 7(12)<BR>\n" );
document.write( "S = 84 </SPAN>\n" );
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