document.write( "Question 317579: find the distance between (-2,9) and (-5,15)\r
\n" ); document.write( "\n" ); document.write( "a) 18.67
\n" ); document.write( "b) 45.02
\n" ); document.write( "c) 6.71
\n" ); document.write( "d) 24.18
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Algebra.Com's Answer #227469 by checkley77(12844)\"\" \"About 
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(-2,9) and (-5,15)
\n" ); document.write( "X d9stance=-2+5=3 units.
\n" ); document.write( "Y distance=15-9=6 units.
\n" ); document.write( "a^2+b^2=c^2
\n" ); document.write( "3^2+6^2=c^2
\n" ); document.write( "9+36=c^2
\n" ); document.write( "c^2=45
\n" ); document.write( "c=sqrt45
\n" ); document.write( "c=6.71 ans. C) for the distance.
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