document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317626>Question 317626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone show me the steps on how to solve this type of problem.\r<BR>\n" );
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document.write( "(a-5)/(2)= (3a)/(2)+(a-30)/(6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227453 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a-5)/(2)= (3a)/(2)+(a-30)/(6)<BR>\n" );
document.write( "(a-5)/2-(3a)/2=(a-30)/6<BR>\n" );
document.write( "(a-5-3a)/2=(a-30)/6 <BR>\n" );
document.write( "(-2a-5)/2=(a-30)/6 multiply by 6.<BR>\n" );
document.write( "3(-2a-5)=a-30<BR>\n" );
document.write( "-6a-15=a-30<BR>\n" );
document.write( "-6a-a=-30+15<BR>\n" );
document.write( "-7a=-15<BR>\n" );
document.write( "a=-15/-7<BR>\n" );
document.write( "a=15/7 ans.<BR>\n" );
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