document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317507>Question 317507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is one-third as long as its height. If the area of the triangle is 24 square meters how long is its base? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227372 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> base = (1/3)x <BR>\n" );
document.write( "height = x <BR>\n" );
document.write( "area = 24 <BR>\n" );
document.write( "Formula needed is A = 1/2 times base times height. <BR>\n" );
document.write( "24 = (1/2)(1/3)(x) times (x) <BR>\n" );
document.write( "24 = (x/6) (x) <BR>\n" );
document.write( "24 = x^2/6 <BR>\n" );
document.write( "24*6 = (x^2/6)*6 <BR>\n" );
document.write( "144 = x^2 <BR>\n" );
document.write( "sqrt{144} = sqrt{x^2} <BR>\n" );
document.write( "12 = x <BR>\n" );
document.write( "The height is 12 meters. <BR>\n" );
document.write( "The base is 1/3 of 12 or 4 meters. <BR>\n" );
document.write( "Done! <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );