document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317512>Question 317512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle is 5 times as long as it is wide. If the area is 125 square feet, find its perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227367 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = 5x\r<BR>\n" );
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document.write( "width = x\r<BR>\n" );
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document.write( "area = 125\r<BR>\n" );
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document.write( "A = L*W\r<BR>\n" );
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document.write( "125 = (5x)(x)\r<BR>\n" );
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document.write( "125 = 5x^2\r<BR>\n" );
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document.write( "125/5 = x^2\r<BR>\n" );
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document.write( "25 = x^2\r<BR>\n" );
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document.write( "sqrt{25} = sqrt{x^2}\r<BR>\n" );
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document.write( "5 = x\r<BR>\n" );
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document.write( "The width is 5 feet.\r<BR>\n" );
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document.write( "The length is 5 times 5 feet or 25 feet.\r<BR>\n" );
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document.write( "To find the perimeter, we use P = 2L + 2W.\r<BR>\n" );
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document.write( "P = 2(25) + 2(5)\r<BR>\n" );
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document.write( "P = 50 + 10\r<BR>\n" );
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document.write( "P = 60 feet.\r<BR>\n" );
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document.write( "Done!<BR>\n" );
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