document.write( "Question 317452: a fort is provisioned for 42 days; after 10 days a reinforcement of 200 men arrives and the food will now last only for 24 days . how many men were there in the fort? \n" ); document.write( "
Algebra.Com's Answer #227313 by stanbon(75887)\"\" \"About 
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A fort is provisioned for 42 days ; after 10 days a reinforcement of 200 men arrives and the food will now last only for 24 days . how many men were there in the fort?
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\n" ); document.write( "Let original number of men in the fort = \"x\".
\n" ); document.write( "(food in fort)/x = 42 days
\n" ); document.write( "(ff)/42 = x
\n" ); document.write( "------
\n" ); document.write( "After 10 days:
\n" ); document.write( "Amt of original food remaining = (32/42)(ff) = (16/21)ff
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\n" ); document.write( "Equation:
\n" ); document.write( "(16/21)(ff)/(x+200) = 24
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\n" ); document.write( "Substitute for (ff) and solve for \"x\":
\n" ); document.write( "(16/21)(42x)/(x+200) = 24
\n" ); document.write( "---
\n" ); document.write( "16(2x) = 24x + 4800
\n" ); document.write( "32x = 24x + 4800
\n" ); document.write( "8x = 4800
\n" ); document.write( "x = 600 men (number of men in the fort before 200 more arrived)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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