document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=317397>Question 317397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two buses leave towns 594 km apart at the same time and travel toward each other. One bus travels 12 km/h slower than the other. If they meet in 3 hours, what is the rate of each bus? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #227261 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=227261\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the speed of one bus be x kmph<BR>\n" );
document.write( "the other bus speed will be x-12 kmph.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Time travel by both = 3 hours<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Distance = rate * time<BR>\n" );
document.write( "distance traveled by first bus = 3x<BR>\n" );
document.write( "distance traveled by second bus = 3(x-12)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+3(x-12) = 594<BR>\n" );
document.write( "3x+3x-36=594<BR>\n" );
document.write( "6x-36=594<BR>\n" );
document.write( "6x=558<BR>\n" );
document.write( "x= 558/6<BR>\n" );
document.write( "x=93 kmph speed of first bus<BR>\n" );
document.write( "speed of second bus = 93-12=81 kmph<BR>\n" );
document.write( "..<BR>\n" );
document.write( " </SPAN>\n" );
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