document.write( "Question 317379: mix a solution that is 50% acid with a solution that is 100% water to make 4 liters of a solution that is 10% acid. How much of each solution is used?\r
\n" ); document.write( "\n" ); document.write( "This is what I have (4-x)*(50/100) = 4x*10/100
\n" ); document.write( " 50(4-x) = 40
\n" ); document.write( " 200-50x = 40
\n" ); document.write( " 200(-200)-50X = 40-200
\n" ); document.write( " -50x = -160
\n" ); document.write( " -50x = -160
\n" ); document.write( " 50 50
\n" ); document.write( " x = -3.2
\n" ); document.write( "So -3.2 liters of water with 0.8 liters of 50% solution to get 4 liters with a 10% percent solution of acid. \r
\n" ); document.write( "\n" ); document.write( "I'm not sure if this is right. I have been working on it for so long I keep making stupid mistakes.
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Algebra.Com's Answer #227255 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "You almost have it. It is just that your answer comes up with the wrong sign. Doesn't make much sense to add a negative amount of water to an acid solution, now does it?\r
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\n" ); document.write( "\n" ); document.write( "You actually set the problem up correctly, but you made a small error when you divided both sides by 50.\r
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\n" ); document.write( "\n" ); document.write( "So\r
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\n" ); document.write( "\n" ); document.write( "and therefore\r
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\n" ); document.write( "\n" ); document.write( "Meaning 3.2 liters of water and 0.8 liters of the 50% acid solution.\r
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\n" ); document.write( "\n" ); document.write( "There is a much less complex way to do this one. First off, let represent the amount of acid solution needed. Then, realizing that 50% is the same as one-half, and 10 percent of 4 liters is 0.4 liters, you can write:\r
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\n" ); document.write( "\n" ); document.write( "And we get the same answer: 0.8 liters of acid solution and 3.2 liters of water.\r
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