document.write( "Question 317374: (2x-3)/3-(3x+1)/5 \n" ); document.write( "
Algebra.Com's Answer #227238 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "When dealing with adding or subtracting fractions we need the denominator to be the same.
\n" ); document.write( "(2x-3)/3-(3x+1)/5
\n" ); document.write( "For this we multiply the first fraction by 5/5 and the second by 3/3 to get:
\n" ); document.write( "5(2x-3)/15-3(3x+1)/15
\n" ); document.write( "Now we can rewrite this as:
\n" ); document.write( "(10x-15)/15-9x-3/15
\n" ); document.write( "This then can be rewritten as:
\n" ); document.write( "(10x-15-9x-3)/15
\n" ); document.write( "With me so far? Combine like terms to get:
\n" ); document.write( "x-18/15
\n" ); document.write( "There we go.
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "www.math-unlock.com
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