document.write( "Question 317208: For how many positive, three-digit integers is one of the digits equal to the sum of the other two digits? \n" ); document.write( "

Algebra.Com's Answer #227181 by JBarnum(2146) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "112,121,211:1+1=2:makes 3 combos
\n" ); document.write( "123,132,231,213,321,312:1+2=3:makes 6 combos
\n" ); document.write( "134,143,314,341,413,431:1+3=4:makes 6 combos
\n" ); document.write( "145:6 combos
\n" ); document.write( "156:6 combos
\n" ); document.write( "167:6 combos
\n" ); document.write( "178:6 combos
\n" ); document.write( "189:6 combos
\n" ); document.write( "

\n" ); document.write( "224:3 combos
\n" ); document.write( "235:6 combos
\n" ); document.write( "246:6 combos
\n" ); document.write( "257:6 combos
\n" ); document.write( "268:6 combos
\n" ); document.write( "279:6 combos
\n" ); document.write( "

\n" ); document.write( "336:3 combos
\n" ); document.write( "347:6 combos
\n" ); document.write( "358:6 combos
\n" ); document.write( "369:6 combos
\n" ); document.write( "

\n" ); document.write( "448:3 combos
\n" ); document.write( "459:6 combos
\n" ); document.write( "thats all possible since 4+6=10 and 5+5=10
\n" ); document.write( " $\"16%2A6%2B4%2A3=96%2B12\"$ =108 possible 3 digit numbers\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );