document.write( "Question 317206: solve algerbraically over the interval (0,2pi)
\n" ); document.write( "2sin^2(x)+3=4 \r
\n" ); document.write( "\n" ); document.write( "I don't know what I'm supposed. I have a million problems to do just like it. I need steps.
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Algebra.Com's Answer #227075 by nerdybill(7384)\"\" \"About 
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solve algerbraically over the interval (0,2pi)
\n" ); document.write( "2sin^2(x)+3=4
\n" ); document.write( ".
\n" ); document.write( "2sin^2(x)=1
\n" ); document.write( "sin^2(x)=1/2
\n" ); document.write( "take the square root of both sides:
\n" ); document.write( "sin(x) = \"sqrt%281%2F2%29\"
\n" ); document.write( "Normalizing:
\n" ); document.write( "sin(x) = \"sqrt%282%29%2F2\"
\n" ); document.write( ".
\n" ); document.write( "Now, using the \"unit circle\" discover what angle satisfies the above and it would be:
\n" ); document.write( "(pi)/4 and 3(pi)/4
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