document.write( "Question 317206: solve algerbraically over the interval (0,2pi)
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document.write( "2sin^2(x)+3=4 \r
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document.write( "I don't know what I'm supposed. I have a million problems to do just like it. I need steps. \n" );
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Algebra.Com's Answer #227075 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! solve algerbraically over the interval (0,2pi) \n" ); document.write( "2sin^2(x)+3=4 \n" ); document.write( ". \n" ); document.write( "2sin^2(x)=1 \n" ); document.write( "sin^2(x)=1/2 \n" ); document.write( "take the square root of both sides: \n" ); document.write( "sin(x) = \n" ); document.write( "Normalizing: \n" ); document.write( "sin(x) = \n" ); document.write( ". \n" ); document.write( "Now, using the \"unit circle\" discover what angle satisfies the above and it would be: \n" ); document.write( "(pi)/4 and 3(pi)/4 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |