document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=36939>Question 36939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A movie theater charges $8.00 for adults, $4.50 for children, and $6.00 for senior citizens.  On one day 405 tickets were sold for a total $2320.00.  If there are twice as many children tickets as adult tickets, then how many of each group were sold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #22707 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=22707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+2X+S=405 OR 3X+S=405 OR S=405-3X & \r<BR>\n" );
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document.write( "800X+450*2X+600S=232000 SUBSTITUTING 405-3X FOR S WE GET\r<BR>\n" );
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document.write( "800X+450*2X+600(405-3X)=232000 OR 800X+900X+243000-1800X=232000 OR\r<BR>\n" );
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document.write( "1700X-1800X=-11000 OR -100X=-11000 OR X=110 THEN 2X=220 & S=405-3*110 OR \r<BR>\n" );
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document.write( "S=405-330 OR S=75 OR 800*110+450*220+600*75=232000 OR \r<BR>\n" );
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document.write( "88000+99000+45000=232000 OR 232000=232000\r<BR>\n" );
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document.write( "THEREFORE THERE WERE 110 ADULT TICKETS, 220 CHILDREN TICKETS & 75 SENIOR TICKETS </SPAN>\n" );
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